### How to use Array of integer Pointers in C

Array of pointers to integers.i.e.Array of integer pointers.Since,Integer pointer store address of one integer.Therefore,Array of pointers to integers will store addresses many integers.
#include<stdio.h>
int main()
{
int a[]={10,20,30};/*array of integers*/
int* arr[]={a,a+1,a+2};/*array of integer pointers so contains addresses*/

printf("\nAddresses of integers:\n");
printf("address of a=%u\n",a);/*no & needed as name of the array gives base address.*/
printf("address of a+1=%u\n",(a+1));
printf("address of a+2=%u\n",a+2);

printf("\nAddrs of integers are stored in arr so each arr[i] is an address:\n");
printf("arr=%u\n",arr);
printf("arr=%u\n",arr);
printf("arr=%u\n",arr);

printf("\nsince arr[i] are address so *arr[i] gives values stored at address stored in them\n");
printf("\narr=%u\n",*arr);
printf("arr=%u\n",*arr);
printf("arr=%u\n",*arr);
return 0;
}
/*
Addresses of integers:
address of a=3216726456
address of a+1=3216726460
address of a+2=3216726464

Addrs of integers are stored in arr so each arr[i] is an address:
arr=3216726456
arr=3216726460
arr=3216726464

since arr[i] are address so *arr[i] gives values stored at address stored in them

arr=10
arr=20
arr=30
*/